Tom and Henry have a 100 meter race and Tom manages to finish the race with Henry still 5 meters behind. They both agree to race again, but this time Tom will start 5 meters behind the starting line to give Henry a chance. Both runners run the second race exactly as the first. Who won the second race?
Tommy Boy must've been going faster to beat the other guy the first time, so at 5 meters before the end of the second race, they were neck and neck. Since Tommy was going faster, he finished first again.
Race 1 (100m all) Tom covers 100m to Henry's 95m. Tom 1 : .95 Henry Race 2 (105m for Tom, 100m for Henry) Tom does 1 * 105 m = 105 m (100m course + 5m delay) In the time that Tom covers his 105m, Henry only covers 105m * .95 = 99.75m So, Tom wins again, except this time by .25m instead of 5m (as in race 1). Also, we assume Tom can run his extra 5m at the same pace as the first 100m. Correct, or not?
You got it! Tom runs 100 meters for every 95 meters Henry runs. So the equation I used was: 100/95 = 105 / X cross multiply and you get 100X = 9,975 X = 99.75 Therefore, after Tom runs his 105 meters, Henry has only covered 99.75 meters of the race. Anyone got any puzzles?
There is a system for pricing these items. Please determine how much the chocolate should cost. ICE CREAM -- 32 cents LOLLIPOP -- 34 cents JAWBREAKER -- 42 cents GUM -- 13 cents CHOCOLATE -- ?? cents
My guess is Vowels are worth 3 cents Consonants are worth 5 cents So... 3v + 5c = ans. Ice Cream = 3*4 + 5*4 = 32 Lollipop = 3*3 + 5*5 = 34 Jawbreaker = 3*4 + 5*6 = 42 Gum = 3*1 + 5*2 = 13 Chocolate = 3*4 + 5*5 = 37 Chocolate is priced 37 cents. P.S. My friend Matt, a.k.a. "The Weaseler" gave me assistance on this one.
I did it a little differently. Time is constant Distance Tom = 100 Henry = 95 difference = 5 95/5 = 19 Tom runs Henry+1/19 Henry 105/ 1+(1/19) = 99.75