Cumulative Loss Formula

Discussion in 'Risk Management' started by dima777, Oct 2, 2008.

  1. MTE

    MTE

    Why are the results illogical? It exactly demonstrates the power of compounding, well, in this case in reverse. As you lose your absolute bet size decreases since you are always risking 1% of your current capital. In other words, you are losing a progressively lower amount. Thus it takes more trades to lose the same percentage of the intial capital.
     
    #11     Oct 3, 2008
  2. asap

    asap


    yes you are.

    taking you to 30% bankroll (a 70% loss) will need 120 trades.

    50% loss = ~70 trades
    70% loss = ~120 trades
     
    #12     Oct 3, 2008
  3. dima777

    dima777


    we must be talking about different percentage here - i am talking about pure loss - while are talking about the amount that is left.
     
    #13     Oct 3, 2008
  4. dima777

    dima777

    thanks I am aware of the exponential nature of the compounding (both up and down) - the progressive diminishing of the losses is nothing new to me...I am talking about the formula itself....
     
    #14     Oct 3, 2008
  5. MTE

    MTE

    Are you talking about the formula I posted?
     
    #15     Oct 3, 2008
  6. dima777

    dima777

    After checking this formula I corrected it to:

    =CEILING(LOG(1-B1,(100-A1)/100),1)
     
    #16     Oct 3, 2008
  7. MGJ

    MGJ

    Isn't it 100x more satisfying when you work out an answer to a problem, all by yourself, instead of looking it up in a musty old book, or blindly trusting the confident pronouncements of total strangers? (including, of course, total strangers who write books or create web pages or post messages to chat forums). Your answer may be right, it may be wrong, but gosh darn it, it's yours. Now that you've "checked" and "corrected" this formula, you probably have a lot of confidence in it.

    By the way, this is the first time I've ever seen the Excel "LOG" function used with two arguments, in an Elite Trader posting. Of course it's perfectly legal in Excel to send two arguments to the LOG function, but it's also highly unorthodox. Congratulations on having the guts to write formulas and get results your way, convention be damned!
    Code:
     first argument = 1-B1
    second argument = (100-A1)/100
    
     
    #17     Oct 3, 2008
  8. dima777

    dima777

    thank you for your supportive words..but i have to note that this formula is just a tiny piece in the ton of other things that I need to finish - so getting help from people who know this is not that bad, after all..:) BTW..thanks for your compliment regarding my guts lol
     
    #18     Oct 3, 2008
  9. ------------------------------------------
    My formula posted (which is equivalent to MTE's later post btw) shows how many trades to get to the remaining balance as a percentage
    of original capital. i.e. 30% of original capital, where CL=30%

    ntrades = ln(CL)/[ln(1-lt)]

    ntrades = number of trades to get to CL
    CL = Cumulative loss
    lt = loss/trade
    ----------------------------------------------
    I was thrown off a bit by some of the earlier posts; particularly when you use 50% which gives the same answer in both instances.:p

    What you really wanted was 1-CL, or the amount you would have to lose to get to some percentage of the original capital.

    simply change formula to:

    ntrades = ln(1-CL)/[ln(1-lt)]

    where the variable, lt, is the absolute value of loss each trade.

    you'll get the same results as the formula
    (can use the ceiling function to round up as well) you posted, which in simple math says:
    logyx=n (excel's argument reverses the terms)
    here y is base :

    where x = 1-CL
    y = (100-lt)/100
    or alternatively,
    (1-lt/100)^n = 1 - CL

    the only other difference is you have it so B1 (1-CL) is entered as a raw value reflecting a percentage, yet A1 is entered as the value that is converted to the raw percentage value. Both of my variables are entered directly as raw values reflecting the percentage.
    i.e.

    =CEILING(LOG(1-F11,1-F10),1)
    =CEILING(LN(1-F11)/(LN(1-F10)),1)
    should both give same,
    where
    Fll = final percentage of original principle
    F10 = percentage loss per trade

    ex :
    F10 = loss/trade = 1/100
    F11 = final percentage of principle = 30/100
    both return 36.

    Cheers
     
    #19     Oct 3, 2008