And here's the proof that common sense is not so common. It's a free bet - the cost to play is zero - they are by definition both excellent bets because the expectancy on both is an infinite multiple of the risk.
(a) Card #1 = 13/52 chance Card #2 = 13/51 chance Card #3 = 13/50 chance Card #4 = 13/49 chance (b) Card #1 = 52/52 chance Card #2 = 39/51 chance Card #3 = 26/50 chance Card #4 = 13/49 chance I'd say B looks easier
That's the best answer I have seen! Commonsensical all the way. B is the best probability of prevailing.